SAT Math · Geometry and Trigonometry

The unit circle

Sine, cosine, and radians from one circle, with the values SAT Math expects you to know.

Updated

At 30°, or π/6, the point is (\tfrac√(3)2, 1/2).30°(√3/2, 1/2)(1, 0)(0, 1)(−1, 0)(0, −1)

(x,y)=(cos⁡θ,sin⁡θ)(x, y) = (\cos\theta, \sin\theta)

At 30∘30^\circ, or π6\tfrac{\pi}{6}, the point is (32,12)\left(\tfrac{\sqrt{3}}{2}, \tfrac{1}{2}\right).

What is the unit circle?

(x,y)=(cos⁡θ, sin⁡θ)(x, y) = (\cos\theta,\ \sin\theta)

A circle of radius 1 centered at the origin. Swing an arm of length 1 counterclockwise through an angle θ\theta. Wherever its tip lands, the xx-coordinate is cos⁡θ\cos\theta and the yy-coordinate is sin⁡θ\sin\theta. That is the entire definition.

The tip of a radius-1 arm at angle θ is (cos θ, sin θ).θ(cos θ, sin θ)(1, 0)(0, 1)(−1, 0)(0, −1)
The tip of a radius-1 arm at angle θ is (cos θ, sin θ).

Why the legs are cos θ and sin θ

cos⁡θ=x1=x\cos\theta = \dfrac{x}{1} = xsin⁡θ=y1=y\sin\theta = \dfrac{y}{1} = y

Drop a line from the point to the xx-axis: a right triangle with hypotenuse 1. SOH-CAH-TOA divides each leg by the hypotenuse, and dividing by 1 changes nothing. So the legs are not just related to cosine and sine; they are cosine and sine.

Hypotenuse 1, so the legs are exactly cos θ and sin θ.θcos θsin θ1(1, 0)(0, 1)(−1, 0)(0, −1)
Hypotenuse 1, so the legs are exactly cos θ and sin θ.

Past 90°, only the signs change

135∘  →  (−22, 22)135^\circ \;\to\; \left(-\tfrac{\sqrt{2}}{2},\ \tfrac{\sqrt{2}}{2}\right)

Every angle makes the same triangle as some first-quadrant angle, flipped across an axis. The side lengths repeat; the quadrant decides the signs. Learn the triangles for 30∘30^\circ, 45∘45^\circ and 60∘60^\circ, and you know every special point.

The 135° triangle is the 45° triangle reflected across the y-axis.135°(−√2/2, √2/2)(1, 0)(0, 1)(−1, 0)(0, −1)
The 135° triangle is the 45° triangle reflected across the y-axis.

Where the values come from

Answer each question in your head, then scroll for the answer.

At 30°, or π/6, the point is (\tfrac√(3)2, 1/2).30°(√3/2, 1/2)(1, 0)(0, 1)(−1, 0)(0, −1)

Think it through

  1. Question 1

    Drop a line from the point straight down to the xx-axis. What shape do you get?

  2. Answer

    A right triangle with hypotenuse 1. Its legs are cos⁡θ\cos\theta across and sin⁡θ\sin\theta up.

  3. Question 2

    At 30∘30^\circ, which special triangle is that, and what are its legs?

  4. Answer

    A 30-60-90 triangle with hypotenuse 1: legs 12\tfrac{1}{2} and 32\tfrac{\sqrt{3}}{2}, so the point is (32,12)\left(\tfrac{\sqrt{3}}{2}, \tfrac{1}{2}\right).

  5. Question 3

    Now go to 150∘150^\circ. What changes?

  6. Answer

    Same size values, but in Quadrant II xx is negative: (−32,12)\left(-\tfrac{\sqrt{3}}{2}, \tfrac{1}{2}\right).

Try it yourself

Work it out first, then check your answer. SAT-style questions, not official College Board questions.

The unit circle with an angle of 150 degrees, which is 5π/6 radians.150°5π/6(1, 0)(0, 1)(−1, 0)(0, −1)

Question 1

What is 150∘150^\circ in radians?

The unit circle at 2π/3, or 120 degrees, where the point is (−1/2, √3/2).2π/3(−1/2, √3/2)(1, 0)(0, 1)(−1, 0)(0, −1)

Question 2

What is the value of cos⁡(2π3)\cos\left(\tfrac{2\pi}{3}\right)?

A right triangle with acute angles x and 90 minus x. The side opposite x is adjacent to 90 minus x.x°(90 − x)°same side

Question 3

In a right triangle, one acute angle measures x∘x^\circ, and sin⁡(x∘)=0.6\sin(x^\circ) = 0.6. What is cos⁡((90−x)∘)\cos\big((90 - x)^\circ\big)?

The unit circle with a point in Quadrant IV at (3/5, −4/5).θ(3/5, −4/5)(1, 0)(0, 1)(−1, 0)(0, −1)

Question 4

A point on the unit circle lies in Quadrant IV and has an xx-coordinate of 35\tfrac{3}{5}. What is its yy-coordinate?

Stuck on a question like this?

Talk it through with Aristotle. It asks guiding questions instead of giving the answer. Intro is free with three sessions.

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The key facts

A point on the circle

(x,y)=(cos⁡θ,sin⁡θ)(x, y) = (\cos\theta, \sin\theta)

Cosine is how far across, sine is how far up.

Pythagorean identity

sin⁡2θ+cos⁡2θ=1\sin^2\theta + \cos^2\theta = 1

Every point on the circle satisfies x2+y2=1x^2 + y^2 = 1, so this holds for every angle.

Degrees to radians

180∘=π radians180^\circ = \pi \text{ radians}

Multiply degrees by π180\tfrac{\pi}{180} to get radians. Multiply radians by 180π\tfrac{180}{\pi} to get degrees.

Arc length

s=rθs = r\theta

With θ\theta in radians. On the unit circle r=1r = 1, so the arc length equals the angle.

First-quadrant values to know
DegreesRadianscos⁡θ\cos\theta (xx)sin⁡θ\sin\theta (yy)
0∘0^\circ001100
30∘30^\circπ6\tfrac{\pi}{6}32\tfrac{\sqrt{3}}{2}12\tfrac{1}{2}
45∘45^\circπ4\tfrac{\pi}{4}22\tfrac{\sqrt{2}}{2}22\tfrac{\sqrt{2}}{2}
60∘60^\circπ3\tfrac{\pi}{3}12\tfrac{1}{2}32\tfrac{\sqrt{3}}{2}
90∘90^\circπ2\tfrac{\pi}{2}0011

Try it

Walk around the unit circle

Step through the special angles and watch the point and signs change.

The unit circle at 45 degrees.45°(√2/2, √2/2)(1, 0)(0, 1)(−1, 0)(0, −1)
45° = π/4

Point(√2/2, √2/2), in quadrant I

cos θ√2/2

sin θ√2/2

tan θ1

Common mistakes

Swapping sine and cosine

Cosine is the xx-coordinate and sine is the yy-coordinate. Alphabetical order helps: (x,y)(x, y) goes with (cos⁡,sin⁡)(\cos, \sin).

Leaving the calculator in the wrong mode

Radians in, degree mode on: every answer is wrong. Check the setting first.

Forgetting the sign past 90°

Find the value from the reference angle, then decide the sign from the quadrant. cos⁡120∘\cos 120^\circ is −12-\tfrac{1}{2}, not 12\tfrac{1}{2}.

Flipping the conversion factor

Degrees to radians is ×π180\times \tfrac{\pi}{180}. If your answer for 90∘90^\circ is not π2\tfrac{\pi}{2}, the fraction is upside down.

How it shows up on the SAT

Geometry and Trigonometry is about 15% of SAT Math. The unit circle is not on the reference sheet, but the special triangles are. Expect radians, special-angle values, and sin θ = cos(90° − θ).

What Aristotle tracks in circles

7 SAT Math skills, including:

  • Solving problems using circle properties

  • Using radians and trigonometric ratios in the unit circle

  • Writing equations for circles in the xy-plane

  • Relating circle equations to circle graphs

Questions students ask

A few things you might wonder before getting started.

What is the unit circle?

The unit circle is a circle with radius 1 centered at the origin of the coordinate plane. The point at angle θ on the circle has coordinates (cos θ, sin θ), which is how it defines sine and cosine for every angle.

How do you memorize the unit circle?

Is the unit circle on the SAT?

Is the unit circle on the SAT reference sheet?

How do you convert degrees to radians?

How can Aristotle help with SAT trigonometry?

A learner having an idea, surrounded by maps and equations

Practice it out loud

Talk it through with Aristotle

Work a question like these out loud. Aristotle guides you one step at a time, so you can do the next one on your own.